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SPOJ - ENIGMATH solution C++

Problem Statement: ENIGMATH - PLAY WITH MATH
Heuristic: Ax - By = 0  has two possible cases:
  1.  a can divide b or if b can divide a and you can figure out the rest.
  2.  a or b cannot divide the other so it will be A B - B A = 0, but we still have to find the minimum x & y.



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